In the following sequence of reaction,CH_3Br | vedclass

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(D) $CH_3Br$ $\xrightarrow{KCN} CH_3CN (A)$ $\xrightarrow{H_3O^{+}} CH_3COOH (B)$ $\xrightarrow{LiAlH_4} CH_3CH_2OH (C)$$1$. $CH_3Br$ reacts with $KCN

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Ethyl alcohol

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(D) $CH_3Br$ $\xrightarrow{KCN} CH_3CN (A)$ $\xrightarrow{H_3O^{+}} CH_3COOH (B)$ $\xrightarrow{LiAlH_4} CH_3CH_2OH (C)$$1$. $CH_3Br$ reacts with $KCN$ via nucleophilic substitution to form acetonitrile $(CH_3CN)$.$2$. Acidic hydrolysis of $CH_3CN$ yields acetic acid $(CH_3COOH)$.$3$. $LiAlH_4$ is a strong reducing agent that reduces the carboxylic acid group $(-COOH)$ to a primary alcohol $(-CH_2OH)$.Thus,the final product $(C)$ is ethyl alcohol $(CH_3CH_2OH)$.

In the following sequence of reaction,$CH_3Br$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_3O^{+}} (B)$ $\xrightarrow{LiAlH_4, \text{ ether}} (C)$. The end product $(C)$ is

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